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-5x^2=3x^2-5x
We move all terms to the left:
-5x^2-(3x^2-5x)=0
We get rid of parentheses
-5x^2-3x^2+5x=0
We add all the numbers together, and all the variables
-8x^2+5x=0
a = -8; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-8)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-8}=\frac{-10}{-16} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-8}=\frac{0}{-16} =0 $
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